2005-4-17 17:35
柯仔
你能在下面的數式中加上【加減乘除或括號】等符號,使它成為一條相等的數式嗎?
1 2 3 4 5 = 1
1 2 3 4 5 = 2
1 2 3 4 5 = 3
1 2 3 4 5 = 4
1 2 3 4 5 = 5
1 2 3 4 5 = 6
1 2 3 4 5 = 7
1 2 3 4 5 = 8
1 2 3 4 5 = 9
1 2 3 4 5 = 10
2005-4-19 17:40
波子
**** Hidden Message *****
唔知答案岩唔岩呢= ="
2005-4-22 20:32
雷達
其實方法都未必只係一種既.............
2005-7-18 17:06
尼奧寵物
1. 1 +2 - 3 - 4 +5 = 1
9. 1+2-3+4+5=9
8. 1+2x3-4+5=8
6. 1x2+3-4+5=6
5. 1+2+3+4-5=5
4. 1-2x3+4+5=4
7. 1+2+3-4+5=7
10. (1+2)÷3+4+5=10 /1+2+3x4-5=10
2 . (1+2)÷3-4+5=2
3. (-1)(2)(3)+4+5=3
2006-1-25 16:40
@周志剛@
cc!
2006-1-27 16:00
FLYME
1+2+3-4+5 = 1
1*(-2)+3-4+5= 2
1-2+3-4+5 = 3
1*2+3+4-5= 4
-1+2+3-4+5 = 5
12345= 6
1*2*3-4+5= 7
-1-2-4+3*5 = 8
1+2-3+4+5= 9
4*3-5+2+1= 10
2006-4-22 00:27
肥軒
[(1+2)/3]*(4+5) = 9
[(1+2)/ 3]+ 4 + 5 = 10
我只懂兩題
2006-6-28 18:18
fireangel
個post成年前... 但係我想睇下答案>"<
2006-6-28 22:07
cch529
????
2006-12-24 22:04
alan1589
1. [(1+2)÷3+4]÷5=1
2. 1+2+3+4÷5=2
3. (1+2+3x4)÷5=3
4. (1+23-4)÷5=4
5. 1+2+3+4-5=5
6. 12÷(3x4)+5=6
7. 1+2+3-4+5=7
8. 12-3+4-5=8
9. 1+2-3+4+5=9
10. (1+2+3x4)÷5=10
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